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Degree 2 Radau on a interval

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In this example:
\(\displaystyle l_{0}:v\mapsto v(0)\)

\(\displaystyle \phi_{0} = \frac{\sqrt{6} x^{2}}{3} + 2 x^{2} - 3 x - \frac{\sqrt{6} x}{3} + 1\)

This DOF is associated with vertex 0 of the reference element.
\(\displaystyle l_{1}:v\mapsto v(1)\)

\(\displaystyle \phi_{1} = - \sqrt{6} x^{2} + 4 x^{2} - 3 x + \sqrt{6} x\)

This DOF is associated with vertex 1 of the reference element.
\(\displaystyle l_{2}:v\mapsto v(\tfrac{3}{5} - \tfrac{\sqrt{6}}{10})\)

\(\displaystyle \phi_{2} = - 6 x^{2} + \frac{2 \sqrt{6} x^{2}}{3} - \frac{2 \sqrt{6} x}{3} + 6 x\)

This DOF is associated with edge 0 of the reference element.